I am having trouble figuring out the tag, set, and byte offset fields for a 32-bit MIPS processor with the following cache configurations:
(a) A direct mapped cache with capacity 8192 bytes and block size 32 bytes. (b) A 8-way set associate cache with capacity 2048 bytes and block size 16 bytes.
I would greatly appreciate any help or guidance on this matter. Thank you!
I attempted to use the formula for calculating the number of bits for each field in a cache memory address:
`Tag = 32 - (log2(cache capacity/block size) + log2(block size))
Set/Index = log2(cache capacity/block size)
Byte offset = log2(block size)`
I expected to be able to use this formula to find the number of bits for each field, but I am unsure if this is the correct formula for this specific MIPS processor.
As a result, I am seeking assistance to verify my understanding and solution.
