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schematic

simulate this circuit – Schematic created using CircuitLab

Suppose x amperes passes through the resistor R in circuit 1. Now if both switches in circuit 2 are turned on in synchronized manner, will the current flowing through resistor R be 2x now ? (Assumption : All the capacitors are charged)

Muhammad Muzammil Nawaz
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  • If you solve both circuits and obtain the current through each resistor, what do you get? – a concerned citizen Dec 25 '22 at 17:16
  • Is it possible to close both the switches at the same time in circuit 2 in simulation? – Muhammad Muzammil Nawaz Dec 25 '22 at 17:20
  • Well, if I answer, what will you do? Go and simulate the circuit? Wouldn't that sort of defeat the purpose of me answering (or you asking)? Instead, you could be driven by your own curiosity and do it yourself, so that the joy of discovery for oneself is that much greater. However, I asked about solving the circuit, not simulating it, these are two different things. While you could go the quick way about it (simulation), solving it will give you some more insight, and, IMHO, that should count for more. But that's just me. – a concerned citizen Dec 25 '22 at 17:24
  • Actually I tried to solve it analytically but couldn't do it. – Muhammad Muzammil Nawaz Dec 25 '22 at 17:36
  • I would be much obliged if you can help me with this. @aconcernedcitizen – Muhammad Muzammil Nawaz Dec 25 '22 at 17:39
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    At the instant after both switches are closed, the inductor current will be zero, and therefore the voltage across R1 will be zero. After that it depends on the values of the components. Are L1 and L2 the same? What about C1 and C2? To me, it seems kind of difficult to solve analytically if the component values are different. I am lazy. I would use a simulator. – user57037 Dec 25 '22 at 18:25
  • L1=L2 and C1 = C2 @mkeith – Muhammad Muzammil Nawaz Dec 25 '22 at 18:43
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    OK, if C1 = C2 and L1 = L2 AND if Vc1 = Vc2 at time t=0, THEN you can convert circuit 2 into circuit 1. – user57037 Dec 25 '22 at 19:02
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    "*Actually I tried to solve it analytically but couldn't do it*" -- can you show what you tried? If you do, people will be able to tell you easily where and what went wrong. Otherwise we'll just have to make presumptions, and that's not really how a Q&A site works. – a concerned citizen Dec 25 '22 at 23:08
  • *Is it possible to close both the switches at the same time in circuit 2 in simulation?* Of course. There are time-triggered switch elements :) – Kuba hasn't forgotten Monica Dec 27 '22 at 07:46

1 Answers1

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As pointed out by @mkeith and @a concerned citizen, a simulation helps very much.

Link to file. Made with FREE microcap v12.

Here is the behavior in two configurations.
The same components just changed one initial condition for one capacitor in the double circuit.
Pictures are at starting time ... Oscillations are vanishing.

enter image description here

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Equations are now up to you.

Last example. Switch is in red circle.

enter image description here

Antonio51
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  • Can we explain which initial condition did you changed for one capacitor in double circuit and why ? – Muhammad Muzammil Nawaz Dec 26 '22 at 13:24
  • The thing I changed is the initial voltage of C2 (200 V in place of 100 V). For just seeing the result. And I found a very "different" (oscillatory) behavior. Just a thought. I did not try changing anything else (values of L1, L2, C1, or C2). Interesting to do in simulation first. – Antonio51 Dec 26 '22 at 13:43
  • 1. Are you using PSpice for these simulation? If you still have that simulation file, can you study the effect of change in inductance in double circuit. I-e Increasing L1 and L2 by same value, decreasing them by same value and by introducing some difference in L1 and L2 – Muhammad Muzammil Nawaz Dec 26 '22 at 20:06
  • I am using microcap v12. Will add the link to the software and add a file link in the answer. There is a animated switch you can open. Run transient analysis and click on the switch 2 times to open. – Antonio51 Dec 26 '22 at 21:03