I am asking this in the context of synchronous generators.
From the textbook "The Performance and Design of Alternating Current Machines", page 421, under the heading "3.Synchronous Reactance" of the CHAPTER XVII SYNCHRONOUS MACHINES: THEORY
Leakage reactance results from real self flux linking the armature slot and overhang conductors, producing a corresponding volt drop \$Ix\$...
I understand it mathematically, via Faraday's law of self induction:
$$ e = -L\frac{dI}{dt} =-L \frac{d}{dt} \big(I_0 e^{-j\omega t} \big) = jI\omega L = jIx $$
I can't visualize what is happening really actually. I would be grateful if somebody could explain what overhang conductors (with proper diagram) are and how it acts as self inductance.
