Here's my qualm:
As per the diagram, I can't understand how the trim probe (resistor) affects the meter reading for this thermocouple circuit.
If I understand the diagram correctly, everything is connected in parallel.
For simplicity sake, the thermocouple at a given temperature (say 700°C) could be represented as a voltage source. I could simplify and redraw the diagram as follows:
As the temperature increases, let's say the thermocouple generates a steady 10 V for arguments sake (I know in reality it's much, much smaller). We can see there's 10 A going across our meter represented as a 1 Ω resistor.
If I take out the trim probe, surprise, the current doesn't change over the meter at all!
If the trim probe was in series with the meter, I could understand just fine how it might affect the reading. I'm sure I've grossly misunderstood something or everything and I look forward to learning something here.
Thank you for your time if you made it this far.
