What is the importance of R1 in this circuit? What would happen if I removed R1 and kept VR1?

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depends on what you mean by `remove R1` – jsotola Sep 27 '22 at 23:44
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1think about what VR1 is ... think about its effect on the circuit when it is adjusted to either extreme – jsotola Sep 27 '22 at 23:45
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7are you able to read the component values in the schematic that you posted? – jsotola Sep 27 '22 at 23:47
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1Downvoted because schematic is unreadable. – PStechPaul Sep 28 '22 at 02:48
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1@PStechPaul: Schematic is sufficiently readable to answer the question. I don't understand the down votes. – RussellH Sep 28 '22 at 02:52
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1Yes, I can figure out what is being shown, but it's not that hard to post a clear schematic. I'll give the OP an upvote if they redo the schematic. – PStechPaul Sep 28 '22 at 03:41
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1When an image ends up like that it's because there's some transparency junk in the image. To deal with that, take a screen shot of the image and crop, or use Windows Snipping Tool. – DKNguyen Sep 28 '22 at 17:12
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I'm sorry for the image apearance but , I was in harry.. – Mahmoud Youssef Sep 29 '22 at 17:39
3 Answers
If \$R_{1} = 0\ \Omega \$, and \$V\!R_{1}\$ is adjusted to \$0\ \Omega \$, then the current through the DIAC and the gate of the TRIAC would be too high, causing one or both to be destroyed.
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Thanks , For your answer.. But how do I calculate the value of R1? – Mahmoud Youssef Sep 29 '22 at 17:39
R1 limits the maximum current into the TRIAC gate when VR1 is at 0 Ω.
Because it is only about 1% of VR, it has very little effect on the brightness adjustment range.

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R1 gives you finer control.
Suppose the ideal range of total resistance is 900-1k ohms. You can get that control with a single 1k variable resistor, but you only would use 10% of the pots possible travel. Suppose instead you use 900 ohm fixed resistor in series with a 100 ohm pot. In this case, you get the whole rotation of the pots travel to make your adjustments. I.e. you can set a value with 10x the precision.
@AnalogKid answer is right also. Either of these (or both really) could be the reason.

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