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The Korg Monotron Duo synth uses the TPA6111A2 headphone amp. The circuit they use is largely the same as the one from the datasheet - except for R78, the 470ohm resistor going to ground right after the decoupling capacitors. I'm wondering if anyone can tell me what the purpose of that resistor is. I've built the circuit on a breadboard, but under my testing conditions I can't see any change in the output.

korg monotron schematic showing the headphone output circuit

Kenny Winker
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1 Answers1

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The 470 ohm resistor to ground keeps the headphone output DC level biased to 0V.

The amplifier chip output is biased to VDD/2 so if there resistor is removed, the both capacitor ends would measure VDD/2 volts, and plugging in headphones would charge the cap voltage only via headphone resistance, causing a large snap and could even damage the headphones with the surge of current.

Justme
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