I've seen this question and thought I understood the basic concepts.
When I attempt to solve for phase given \$Z = 60 + j10\$ I end up with 9.46. However, my professor has given the answer as 39.81. I am told that the phase angle of 39.81 is derived from the complex reflection coefficient, and I understand that the reflection coefficient must be complex, but I simply calculate it as 0.128 and don't understand how to derive it as a complex number.
Here is the question exactly as provided:
A signal source, which has a characteristic impedance of 50 ohms, is connected to a load impedance of 60+j10 ohms determine the following:
- a) The return loss;
- b) How much power will enter the load in dBm if the source power is 10mW;
- c) The VSWR (think: will there be many standing waves s present?)
- d) The phase of the signal reflected back to the source.
There was no diagram provided, solely the text above. The answers as provided are as follows:
- (a) Return loss, 17.85dB
- (b) Mismatch Loss, 0.072dB, Power through is 9.928dBm
- (c) VSWR = 1.29
- (d) Phase of the reflection coefficient is 39.81 degrees
I got a, b and c correct which means I must have calculated the reflection coefficient. I know the reflection coefficient needs an imaginary part but I have no idea where the value of it comes from.
I calculated the reflection coefficient to be 0.128.
