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I painted the currents, used the first Kirchhoff's law and got the expression:

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Next, I need to find the voltage transfer coefficient (Ku), that is, the ratio of the output voltage to the input voltage, but I do not quite understand how to do this due to the fact that there is dU(out) and just U(out)

aleksandr
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    Are you familiar with the Laplace transform? If not, select a single frequency for analysis, say, \$\sin(\omega t)\$, express the derivative of that in terms of the signal itself so that only the signal appears in the expression. e.g. \$\frac{d\sin(\omega t)}{dt}= \omega \cdot \sin(\omega t + \pi/2)\$ So for a sinusoidal signal \$|dU| = |\omega U|\$. – AJN May 22 '21 at 12:57
  • Is DA1 an op amp? See this answer for effect of the capacitor: https://electronics.stackexchange.com/a/68710/95488 – ErikR May 22 '21 at 13:22
  • Yes, it is an op amp – aleksandr May 22 '21 at 13:26
  • DC gain is -R2/R1 and AC gain reduces to -3dB when ZC(f)=R2 – Tony Stewart EE75 May 22 '21 at 15:27
  • Your formula with time-derivatives is in the 'time domain' (signals are described as varying in time). Transfer functions (or coefficients if you prefer that term) are in the 'frequency domain' (signal amplitudes are a function of frequency). That's the reason for AJN's advice. – HarryH May 22 '21 at 16:28
  • however, I don't understand how to get from this formula Uout/Uin – aleksandr May 22 '21 at 17:08

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