An electronic load has a specific current vs. voltage function that is it's alone. If you put 5V on it, it will consume as much current as it consumes. As long as the current capability of the 5V supply is greater than the total current taken from it, it will supply 5V*.
Add up the current required for your sensors that need 5V. If it's less than the 1.5A that's available from that pin, then you're fine.
* With exceptions: older wall-warts put out somewhat more voltage at no load (no current taken) and less under heavy load. There are also specialty supplies that are designed for delivering a constant current -- but those are super special, and not something you'll encounter even on a yearly, much less daily, basis.