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Context: Consider a circuit with only two linear time invariant capacitors. If I charge one the capacitors and then throw a switch that closes the circuit, there will be some redistribution of charge. The capacitors are ideal and there is no resistance in the circuit.

Problem

I calculated the energy before the circuit was closed and after the circuit attained a steady state. There was some energy dissipation.

My question is: In what form is the dissipated energy leaving the circuit?

AkaiShuichi
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  • I had a look at the question and the answers however i did not find an answer to my question, which was pertaining to the form in which energy was released by the circuit under ideal conditions (I believe i did mention there are no resistances) – AkaiShuichi Sep 26 '19 at 02:33
  • [This answer](https://electronics.stackexchange.com/questions/75456/decrease-in-stored-energy-after-connection-of-another-capacitor/75490#75490) doesn't satisfy you? – brhans Sep 26 '19 at 03:00
  • profuse apologies for not doing my homework before asking a question here... @brhans the answer did satisfy me, i overlooked the second answer to that question – AkaiShuichi Sep 26 '19 at 03:38
  • The infinite current in the zero ohm resistances tends to account for the losses :-) . | Congratulations on apologising due to an oversight - it's rare. (+1 :-) ). – Russell McMahon Sep 26 '19 at 11:54

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