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The Chua's circuit satisfies the differential equations from Wikipedia.

enter image description here

Clearly, \$x=y=z=0\$ is a solution, but not the solution we see when double scroll appears. Since at \$t=0\$ when we switch on the circuit, \$x,y,z\$ must be all very close to \$0\$, for double scroll to appear, the system must be able to walk away from \$0\$. Therefore, \$0\$ must be an unstable equilibrium if the experiment is successful.

However, whether \$0\$ is an unstable equilibrium or not depends on the parameters. So does it mean that, if the parameters are incorrectly chosen so that \$0\$ is a stable equilibrium, then no double scroll can be observed?

Dave Tweed
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Jethro
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    Double scroll? Define it – Voltage Spike Jul 13 '19 at 04:59
  • This question appears to be a duplicate of [one posted on physics.se](https://physics.stackexchange.com/questions/491310/chuas-circuit-is-x-y-z-0-a-stable-squilibrium). Please don't cross-post on different SE sites. If you've decided that EE is a better site for this question, you can ask the Physics mods to migrate your question over here. – The Photon Jul 13 '19 at 05:27
  • @laptop2d See the picture on wikipedia. – Jethro Jul 13 '19 at 06:10

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