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Lets say I have -2 dBμA/m as a limit.

How do I convert the magnetic field strength in A/m to dBμA/m? Is it as follows?

$$20\cdot \log(\frac{ |H| }{10^{-6}})$$

Thank you!

Defindun
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1 Answers1

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Assuming the units of H are A/m, then dividing by 10^-6 will convert the amperes into microamperes. Taking the logarithm to base 10 of the result and multiplying by 20 will indeed convert the original value in A/m to dB//uA/m. Your formula is correct.

Barry
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