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I'm trying to command a Solid State Relay with the HV1 pin, I can't connect it directly(HV1 to CH1) due to the fact that the impedance on that pin is too low and I only obtain 2.8V when connected.

So, I'm trying to use an NPN transistor(Q1). However, being inexperienced with tranistors I'm not sure that my schematic is correct(probably not).

Can you give me some hints on how to choose the resistor's value, or what should I change to make it work? Thank you!

This question comes after this question (Bidirectional Logic Translator translates to 2.8V instead of ~5) (The "Switch" is actually the SSR)

CH1 is the command pin of the SSR

schematic

simulate this circuit – Schematic created using CircuitLab

1 Answers1

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Usually you control a relay by connecting the "coil" where the resistor is in your diagram.

The transistor allows current through the coil when the command signal is on, and blocks current when the command signal is off.

Also don't forget to put a current-limiting resistor before the base of the transistor.

Like this:

schematic

simulate this circuit – Schematic created using CircuitLab

It should work the same way for an SSR.

Addendum: The reverse "freewheeling diode" D1 is not required with an SSR. However it is required when using a mechanical relay. If you are using this circuit with a mechanical relay, connect the diode in reverse-parallel with the relay coil as shown.

user253751
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