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(solved - solution added at the bottom)

I have a power jack I can't remove. I tried a hot air gun set on 480 °C and a soldering iron set to 480 °C.

While some solder seemed to have melted on a few pins, the other pins didn't seem to be affected. I tried applying flux, and I tried adding more solder with the hope the old solder would stick to the new one. I tried placing the soldering iron on each of these pins for 2 minutes and nothing helped.

Is it possible that some solder will not melt under 480 °C?

An image of the almost destroyed area:

Enter image description here

Enter image description here

My soldering iron photo added as requested in the comments

enter image description here -----Solution-----

After reading all the answers i decided to try again. i set both the soldering iron and the hot air gun to 480C. this time, after reading about the Heat loss i tried removing the tip of the hot air gun (shown in the photo) and voila! it melts!. I pushed each pin out slowly with the soldering iron and the socket was successfully removed. enter image description hereenter image description here

soundslikefiziks
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  • Could you add some pictures of your soldering iron and hot-air station? It could be very relevant information. – Chupacabras Apr 21 '18 at 18:11
  • @Chupacabras Done. – soundslikefiziks Apr 21 '18 at 19:39
  • Sorry to tell you, but that is very poor tool. Incapable of resoldering big components. I have very similar hot air station. I'm using it for heat shrinking and soldiering low mass components. – Chupacabras Apr 21 '18 at 19:45
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    @Chupacabras what makes it bad? sustaining the temperatures or not even reaching them (i never actually measured it ) – soundslikefiziks Apr 21 '18 at 20:04
  • It has very low power, it is the main problem. So it is able to deliver only a fraction of heat required to heat up high mass components. The heat is faster dissipated by huge mass of copper then your heat gun is able to deliver. You need more powerful hot air station than yours for this task. At this moment even when you set 480C on your station, it is not able to heat the board to 230C which is melting point of lead-free solder. – Chupacabras Apr 22 '18 at 06:14
  • are they twisted too? at least pin 3 looks like it. add a desoldering pump to your equipment. – dlatikay Apr 22 '18 at 11:17

8 Answers8

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No, it will be standard solder. Whatever was used on the rest of the board. The problem is that all the metal is conducting the heat away too fast. Also, large number of pins will mean that even when the solder melts you have to pull the (now very hot) part off the board, which is not easy.

One solution is to use a coping saw or similar to slice up the jack, and pliers to crush and break the plastic parts. If you can reduce it to individual pins soldered into holes you should be able to remove them one by one.

The high power hot air guns you get for stripping paint would also get everything hot enough, but might overheat or blow away nearby components if they are not protected somehow.

I also think it should be possible to use hot air and soldering iron to do this, but it would be tricky. You need a large tip to get the heat flowing, and adding more solder can also help transfer heat. Use the hot air to preheat the jack, and surrounding area of the board - ideally from both sides. Use tin foil to protect nearby components from the airflow.

Jack B
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    +1 If you won't reuse this connector, then destroying it and diminishing it to separate pins is the best way to go – Andrejs Gasilovs Apr 21 '18 at 10:51
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    somewhat related: [Cutting off metal anchor legs on an HDMI port or Metal connector? What to use?](https://electronics.stackexchange.com/a/160178/7036) – Nick Alexeev Apr 22 '18 at 17:14
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No, what is happening is that your heat gets 'taken-up' and remove by all the metal in the socket and in the board. You not only need to provide heat, you need to provide heat faster then it gets removed.

A bigger wattage soldering iron will help but in the end if there is just too much metal that does not work either. A hot air gun in combination with a soldering iron is more appropriate for removing components with a lot of metal or if you have large PCB copper areas.

Chris Stratton
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Oldfart
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  • Even if i set my soldering iron to 480C ? – soundslikefiziks Apr 21 '18 at 09:28
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    Yes. Also a small tip prevents heat from getting into the part. I sometimes ADD solder, then when it is all fluid use lots of copper braid to quickly suck it up. – Oldfart Apr 21 '18 at 09:32
  • yes i tried adding solder and when i sucked it up with the copper braid , the old solder still remained on the pin – soundslikefiziks Apr 21 '18 at 09:35
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    I don't use solder wick for stuff like this, it is a waste. Heat a pin, pry the part up a little bit, let it cool. Heat another pin, pry it up, let cool. Repeat until the part pops out, then use solder wick to clean the solder out of the holes. – JRE Apr 21 '18 at 10:58
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    @JRE That's a useful technique, but I think it's good to add a small warning: You have to be careful to not rip the pads up, especially on single-layer boards or pads which are not connected to a trace. – pipe Apr 21 '18 at 12:31
  • @soundslikefiziks: Don't confuse temperature and heat. They are two different things. A piece of wood and a sheet of steel left outside will have the same temperature after about an hour. However the metal will feel colder to the touch. This is because the metal has higher capacity to absorb heat. If you measure again the metal will have the same temperature as the wood – slebetman Apr 22 '18 at 02:35
  • @soundslikefiziks Continuing from the example of the wood and metal (both same temperature but wildly different heat capacity) a small tip soldering iron and a very big flat tip soldering iron can have the same tip temperature. However, the small tip iron will have very little heat in it (less mass) compared to the big flat tip. This means, as soon as the small tip iron starts melting solder it's temperature drops instantly and the heating element in the soldering iron will have to quickly try to reheat the tip. – slebetman Apr 22 '18 at 02:40
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I'll use current as an analogy for heat flow. From Wikipedia:

The heat flow can be modeled by analogy to an electrical circuit where heat flow is represented by current, temperatures are represented by voltages, heat sources are represented by constant current sources, absolute thermal resistances are represented by resistors and thermal capacitances by capacitors.

All the following circuits are simulatable, you can run the DC solver and it will give you temperatures in "Volts". :D

A VERY rough model of your current setup

Lets assume 50W == 50A. I Guessed a total thermal resistance so that the reading on your soldering stating would give 480ºC. (unit for thermalr sistance would be K/W, I'm ignoring ambient temp and a lot of things, but anyhow).

Your soldering tip has a high thermal resistance and the board has a low thermal resistance, so even though the iron is measuring 480ºC in its tip, the PCB is at a much lower temp.

schematic

simulate this circuit – Schematic created using CircuitLab

How to transfer more heat to the board?

Lower the thermal resistance of your tip! That's how tinning your tip to get more surface, fatter tips, etc help. Let's say 2.4K/W is the absolute best tip you can get. Still, 50W is not enough to reach a solderable temperature. (But see that the proportion of temperature got better, you are at 50% of the tips temperature now instead of 25%).

schematic

simulate this circuit

What would more Watts give you?

Since 50W is not enough to heat very low thermal resistance objects (big planes of copper). You add more power until you can reach 480ºC at the reading point. Note that if the object had higher resistance you would need less power.

schematic

simulate this circuit

Preheating the board

I think this would a very rough model for a pre-heated board:

schematic

simulate this circuit

Note how you need less power than the previous example AND that the temperature "proportion" is better.

So in essence, when dealing with heavy temperature sinks:
- More power is good if you can deliver it without losses.
- To lower the losses: a fatter tip, better contact, no wind.
- Higher target temperature: preheat!

Some stations (I use an ERSA i-con) have internal presets for different tips, because they have profiles of temperature loss and transfer and try to compensate for that.

See that it has 2 numbers:

enter image description here

Both read 350ºC, but one is the sensed temperature, the other is the set temperature. So, in case that the power is not enough (As in the example that only reached 240ºC), you could read it out. IRC, those chinese soldering stations blink between sensed and set temperature, but I'm not sure.

Wesley Lee
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Standard tin-lead solder melts at 183°C, lead-free melts somewhere around 221-225°C. Your problem is it doesn't reach this temperature, because the amount of heat you put in is too low, and the amount of heat the board and connector copper mass sucks out is too high.

If you use higher temperatures, like your 500°C paint stripping air gun, yeah sure this will put more heat into the board, but unfortunately the parts that do reach this high temperature will delaminate, and your board will be destroyed, because the temp is too high. When blowing hot air on a board, the large masses of metal will heat slowly (ie, your solder won't melt), but the plasticky bits will heat quickly and risk burning. It's better to use a high air flow rate at a lower temperature, than a low flow rate at a higher temperature. Hot air works well, but it requires a bit of practice.

Solution to your problem, in Ghetto mode.

enter image description here

Use a bit of thick copper wire to bring heat to all pins simultaneously. Pictured here is a chip, but it will work on lots of components if you bend the wire in creative ways. Even capacitors, and other stubborn 2-3-pin thru-hole components! For example, to desolder a thru-hole part with 2 or 3 legs, simply place a bit of 1.5mm2 (AWG16) copper wire along the pins, and heat. Keep it short, add enough leaded solder to conduct heat into all the pads you want to melt, then apply a high-power soldering iron, like a 100W dumb soldering pistol or a temperature controlled iron.

All the pads will melt at the same time. This works like a charm, in a few seconds. It's quick, so the board doesn't char.

bobflux
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Your problem is that the board is a motherboard that is multilayer- it has ground and power planes within that heavily draw heat away from the plated-through holes surrounding pins as you are trying to melt the solder holding them.

You need a good soldering iron, not one set to a high temperature, to provide enough watts to heat the solder to the (normal) melting point. For this it should be set to a moderate temperature, but be capable of delivering many watts on demand (with closed-loop control).

As others have said you may have better luck with your current iron if you physically break apart the connector and try to remove each pin individually. You can also preheat the board with hot air, set to perhaps 120°C, but do not use an uncontrolled paint stripper type of heat gun or you may well damage the board or surrounding components.

Spehro Pefhany
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  • So you are saying i should actually lower the temperature ? and the 120C on the hot air just seems really low (i don't have an uncontrolled paint stripper ) – soundslikefiziks Apr 21 '18 at 19:21
  • 100°C is a more normal preheat temperature. Lowering the temperature on your existing iron won't help you, you need a better iron (which should be set to a lower temperature than 480°C) or better technique. – Spehro Pefhany Apr 21 '18 at 19:23
  • My existing iron is an adjustable temperature one – soundslikefiziks Apr 21 '18 at 19:25
  • About the better technique, i certainly need one ;-) – soundslikefiziks Apr 21 '18 at 19:36
  • I added a photo of the soldering station if that helps. – soundslikefiziks Apr 21 '18 at 19:44
  • @soundslikefiziks -- get a FAT soldering tip! (After you get a decent station) It helps by not losing temperature when it loses heat to board. – Wesley Lee Apr 21 '18 at 19:47
  • Only 50W nominal, not really very good for this kind of situation. You might be able to work it by breaking the connector apart. Don't set it to a very high temperature, just work slowly and carefully, pin by pin. – Spehro Pefhany Apr 21 '18 at 19:52
  • @WesleyLee Thanks for the tip, i am starting to grasp this heat losing thing, but what's wrong with the current soldering station ? – soundslikefiziks Apr 21 '18 at 20:07
  • @SpehroPefhany Excuse my ignorance, but if the heating element in my current soldering iron reaches the higher temperatures that are required, why would the Watts matter ? – soundslikefiziks Apr 21 '18 at 20:09
  • If what you are soldering can sink more heat than your soldering iron can output, doesnt matter if the heating element is at the set temperature, the "object" will not heat up to that temperature. Think of it as a gradient, where all elements have some thermal resistance and your object is a hole that can sink heat. The lower the power output (in Watts), the higher the resistance and larger the hole, lower will be the temperature of your object. 50W is not a large source of heat, a fine tip has "high resistance", a few large copper planes are a "large hole" (for heat). – Wesley Lee Apr 21 '18 at 20:16
  • @WesleyLee so if i somehow measure the tip it won't read 480C ? and a good heating station has a sensor that readjusts the heat in case of heat loss ? – soundslikefiziks Apr 21 '18 at 20:30
  • @soundslikefiziks -- depends on how the manufacturer programmed the station. They could try to compensate for the losses at the tip and put the internal temperature at higher than the preset to give the actual temperature at the tip. but since 480C is quite high I dont think they would go higher than that. I was thinking about my analogy and I wrote an answer with a few very rough models. – Wesley Lee Apr 21 '18 at 21:01
  • The best it can do is turn on the heater 100%. If more heat is required the temperature at the sensor (let alone the tip) will dip. – Spehro Pefhany Apr 21 '18 at 21:01
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You might try indium solder. It will alloy with the tin/lead and give you an alloy with a much lower melting point. There is probably something on YouTube showing how to do this.

Robert Endl
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If you are using the conical soldering iron tip shown in the photo then you need to change it to a different one, probably a "2.4D" tip. A little investigation should enable you to find one that will fit your soldering iron, it will probably come with several other tips - there is no need to get too many other tips, or ones with fancy coatings.

The idea is that a conical tip has very little contact area, so it cannot transfer heat quickly compared to a larger tip. You need the heat transfer.

I found a video showing all the different ways that don't work to change the tip on YouTube: Mounting 900M-T Soldering Iron Tip on Yihua SMD Rework Station.

Andrew Morton
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For completeness, welding connections that cannot be undone with soldering equipment DO exist in (mostly professional) some niche electronics, as does the use of especially high-melting-point solders (eg for downhole equipment).

However, in your case, it is almost certain that there is simply too much heat sinking from the thermal mass of the component itself, as other answers suggest. Try using a larger tip, a larger/stronger iron (keeping a cheap plumber-type iron around for such situations is useful), and probably adding some thermal mass and heat conduction by ADDING molten solder to the joint you are trying to undo.

Clarification: "Downhole" is some category of oil well exploration equipment, that defies all normal rules on what kind of heat electronics can take. Operating temperatures where normal solder would actually melt.

rackandboneman
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