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Let's look at the next circuit:

schematic

simulate this circuit – Schematic created using CircuitLab

Will electric current go through R1 in the real world? Is ground like a conductor with some R supposedly > than R1, and can we illustrate this like that :

schematic

simulate this circuit

koshachok
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    You asked if ground was like some R that is > R1. However, I'm wondering if you meant < R1 (less than) because generally ground is considered 0V and I'm assuming very low (almost negligible) resistance also. Just curious. – raddevus Feb 14 '18 at 18:15
  • Looking at the second schematic, in reality, R2 is nearly 0 ohms. Just the resistance of the connecting wires and however they are joined or clamped to consider. Also, R3 is getting pretty close to 0 ohms. Resistance in parallel circuits explains that there will still be *some* current through R3 almost regardless of its value, however small that amount of current will be. – Willtech Feb 15 '18 at 11:58
  • [this thing](https://www.theshirtlist.com/wp-content/uploads/2015/06/RESISTANCE-ARE-FUTILE.jpg) first comes to mind when I see R1. – Dmitry Grigoryev Feb 15 '18 at 12:20

4 Answers4

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Yes an no.

As a schematic... No. The ground symbol simply means both those wires are the same node and that node is deemed to be your reference ground for measurements. It is an arbitrary and abstract definition of ground. No current ever flows thorough that point to anywhere.

A ground symbol in a schematic is actually only a special net name designator. The following two schematics are equivalent.

enter image description here

As such, what your schematic is internally represented as in any schematic editor is this. Notice GND is a single node/net that isn't actually connected to anywhere outside the circuit.

schematic

simulate this circuit – Schematic created using CircuitLab

Now you may ask what about trace resistance. Well, if you open that can of worms, whether any current flows through R1 would depend on how you routed the ground net.

This way R1, on the right, would carry a small current...

enter image description here

This way, it wouldn't..

enter image description here


If you take your drawing as a "wiring diagram", where each grounding point is a different connection point to either a common ground or physical earth, yes there will be a finite resistance between those points.

In a real schematic you would indicate separate grounds differently.

schematic

simulate this circuit

Trevor_G
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    'no current flows ever flows though that point'? Agreed, if there's only one, but if there are more than one, then current can flow between them. – Neil_UK Feb 14 '18 at 15:16
  • @Neil_UK NO. In a schematic it is merely a special node name designator, and as such both points are the same node. Current cant flow because it has nowhere to go. If it they were separate nodes going to off-board connectors, as in my added schematic, that is different. – Trevor_G Feb 14 '18 at 15:44
  • @Trevor_G, You say that current can't flow in to or out of a ground symbol because all of the ground symbols designate the same particular node in the circuit. So, does that mean that current can't flow in to or out of _any_ node in a circuit? – Solomon Slow Feb 14 '18 at 15:49
  • @jameslarge no I'm saying understanding ground as a "ground" where current sinks to, separate from the supply, is incorrect in the indicated schematic. If you do actually show the ground going somewhere... i.e. through some connector to an actual ground connection, it then becomes a circuit . – Trevor_G Feb 14 '18 at 15:57
  • If you have a resistor in series with a ground symbol, and another ground symbol somewhere else to complete the circuit, then a current can flow through that resistor, wire and symbol to the ground node. Ground symbols have zero impedance, which is arbitrary current at zero voltage, not zero current which would imply infinite impedance. You know all this, so I've a feeling that there's some other finer point of language that we're askew on. – Neil_UK Feb 14 '18 at 16:07
  • @Neil_UK yes indeed, but that resistor changes the circuit nodes. Above the resistor is a different net. People misunderstand the ground symbol as an active component that current goes into, or out of. That is incorrect, it is merely a special NET label. – Trevor_G Feb 14 '18 at 16:18
  • Sigh, I still maintain current can flow through a ground symbol. Have a look at the schematic in my answer, and tell me where the R2 current is flowing, or how you'd draw it. – Neil_UK Feb 14 '18 at 16:39
  • @Neil_UK ![schematic](http://i.stack.imgur.com/84IMb.png) – Trevor_G Feb 14 '18 at 16:48
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    In the last example, a tiny bit or current may flow when the circuit is just energized, because it forms a 1 loop air gapped transformer – Ferrybig Feb 15 '18 at 08:35
  • @Ferrybig like I said..."can of worms" ;D – Trevor_G Feb 15 '18 at 13:36
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Those triangle symbols are usually taken as meaning "0 volts" i.e. the reference voltage by which all measurements are made. They don't necessarily mean copper rods driven into the earth.

Will electric current go through R1 in the real world?

We try and show real-life stuff on a schematic so if those triangles are earth connections then we might show them as impedances connected to a common point labelled as (maybe) "earth rod" or "AC ground" or "chassis".

There will be current through R1 and depending on what a proper schematic informs us we might be able to calculate that current.

Andy aka
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    +1 for adding the trying to show the real world connection details part. ANd congrats for 200k for real this time ;) – Trevor_G Feb 14 '18 at 14:16
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    and another +1 from me and many congrats on your 200k - well deserved. – JIm Dearden Feb 14 '18 at 15:55
  • I tend to use the phrasing "to ground" when I see these symbols. I find it's useful to think of it as though there was a wire to the "ground," and then the meaning of "ground" comes from my context. In the context of a car, "ground" is usually a reference to a connection to the car body, so likely conducts very well. In the context of RF antennas on the roof, these might be seen as separate stakes driven into the ground, with a resistance between them. In either case, "connected to ground" invokes the right meaning for me. – Cort Ammon Feb 14 '18 at 19:37
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It all depends on what level of reality you are trying to represent in your schematic. The important words here are 'you' and 'represent'. You choose what you mean when you draw a schematic.

Ground symbols represent a connection to the same point, the same node, so they all have the same voltage, exactly 0v, with zero resistance between them. In the first circuit therefore, no current would flow through R1. That's what you've drawn, a short circuit across R1.

If you want to represent a realistic resistance between different points, let's say between multiple connection points to the chassis in a car, then you would show resistors, either between points as in your second diagram, or a resistor in series with each ground symbol. Once you have established what the actual shunt resistance is that you have across R1, then you can work out what the current division is between R1 and the path through ground.

For instance, to redraw your first diagram, showing realistic chassis connection resistances, we might have one of the following. I've drawn it in two completely equivalent ways, as some people don't appear to accept the semantics of multiple ground symbols.

schematic

simulate this circuit – Schematic created using CircuitLab

Here we've designated the Rx1/Rx3 junction as the 'true' ground node, it's the point we reference all our voltage measurements to. I've shown a resistance between the Rx1/Vx1 junction and our ground reference point as Rx2. It might be made up of a physical wire that connects that node to the chassis, together with the resistance of the chassis itself. Now we have shown a finite value for the resistance in shunt with Rx1, we can calculate how current will divide between Rx1 and the groundy path through Rx2. In this case, 33% of the current flows through the ground designators and Rx2, and 67% through Rx1.

I'm sure all will agree that a current flows through R22. I'd be interested to know whether people think a current flows through R12, and if so, where it flows.

Neil_UK
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    @Trevor_G I'm thrilled that we all are in violent agreement, but maybe next time this debate should happen in chat. – W5VO Feb 14 '18 at 23:33
  • @W5VO So, why weren't the comments migrated to chat? Any discussion in the comments can be moved to it's own chat room. – Mast Feb 15 '18 at 02:53
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Probably the easiest way to clarify some of your misunderstandings and also bring up some new ideas for you to consider is to see how Spice writes down (to itself) these two schematics:

* TOP SCHEMATIC:
V1 1 0 1
R3 1 0 100
R1 0 0 1u

and,

* BOTTOM SCHEMATIC:
V1 1 0 1
R1 1 2 100
R2 2 0 X
R3 2 0 1u

The universe doesn't actually know anything about the ground reference for your circuit. Everything in the universe is relative and the entire plant Earth might be sitting at a trillion volts relative to some other place in the galaxy, for all we know. And the universe simply doesn't care.

The choice for the ground reference is one you get to make. Normally, a voltage is always measured between two points. Just think about a voltmeter. It has two leads. Not one. That's because a voltage is always really a "voltage difference." But it is painful when talking to people to always have to say, "The voltage is 4 volts here, relative to this point over there." We'd rather just say "The voltage is 4 volts here." So we pick a reference point and it helps a lot in saving time and effort when discussing a circuit.

There is another reason. An input signal (like audio) is often referenced to some specific place in the circuit. If you have one circuit that has its own ground reference and a different circuit that also has its ground reference, and if you tie these ground references together, then both circuits now share the same "reference point." Now you can just convey audio signals from one circuit to the other circuit by way of a single remaining wire. And that's an important physical convenience. This is also why the ground reference is sometimes called the "common." Because it is "common" between several subcircuits that share the same "ground reference."

Now look back up at those schematics as Spice sees them. There are only two different nodes in the first schematic: "0" and "1". But in the second one, there are three nodes: "0" and "1" and "2". All nodes with the same name are connected together (shorted.) If you look closely at the first schematic, you will see that the last line connects both ends of the resistor to the same node, "0". (The value of the resistor is the last word on each line.) Since both ends of the resistor are tied to the same node, this is the same thing as "shorting out the resistor." And so your first circuit simply shorts out \$R_1\$. You might as well just remove it.

I wanted to try a different tact here and see if that helps you. There are lots of ways of trying to explain this and I didn't see this one being tried. So I thought I would add it to the mix.

By the way, Spice also treats the "0" node as very special. It's always the "reference node." So if you try and print out the voltage at a different node, then Spice will use this special node as its "reference" for making a two-point voltmeter measurement. (Spice requires this node in every schematic because it wants to have the convenience of just reporting node voltages without having to always specify two points to do it.)

The ground symbol on a schematic is a notation device, no different from giving a name to any wire. Suppose you write out a schematic and give the name "AUDIO_IN" to one of those wires. Then this wire is now given that name. Suppose somewhere else in the schematic, on a different wire entirely, you also name that wire "AUDIO_IN". (Let's say you don't actually draw a wire line between these two.) This still means that the two wires are actually connected (by a hidden wire.)

Giving the same name to two different wires is, by convention, taken to mean that the two wires are attached to each other --- even if you didn't actually draw a wire connecting them. That's how I'd read it. That's how others would read it. So if you do that, then that's how it will be interpreted. It's how you should learn to write things, too.

Now, the ground symbol is just like a "name" to a wire. If you place a ground symbol on a wire, then this is the exact same thing as giving it a special name "ground." If another wire somewhere else also has the ground symbol attached to it, then even if there is no wire shown on the schematic, it is assumed by everyone reading the schematic that the two wires are now connected together. Because they have the same name -- "ground."

jonk
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  • +1 Yup, exactly. There is no way to tell from the OPs schematic if the thing is attached to earth ground at all since no such connector is indicated. One can assume... but assumptions are a bad thing in engineering and usually come back to bite you. – Trevor_G Feb 14 '18 at 18:54