Why do we use step response?

Question

We tend to identify systems more often by using the step response. Why? Especially when the impulse response is directly related to the transfer function?

Answer 1

Step response and transfer function are interchangeable via Laplace transform (step response -> differentiate to get impulse response -> laplace -> transfer function), but you can't run a Laplace transform on a graph pulled out of a datasheet...

For example, the user of a LDO will usually be interested in things like voltage sag/overshoot when load current steps up and down, so in this context a graph of the step response is useful.

Same if you design the control system for something like a mechanical actuator: the transient response is often more important than transfer function, you'd want to avoid overshoot, avoid excessive slew rate, have good damping, things like that. Step response shows all this in a way that is easy to understand, whereas transfer function will not (instead, it provides more insight into stability, etc).

Also testing the step response is much easier than measuring the transfer function.

And the transfer function is only valid when the system is linear, not when it is slewing. If slew limit is involved, or other large signal conditions, then step response is no longer the Laplace transform of the transfer function, because the system is no longer linear time invariant.

Opamps' datasheets usually give both, since we're both interested in the frequency response, and settling time/ringing/overshoot, clipping recovery, etc.

EDIT: I just realized you asked why step response was used instead of impulse response:

• It is easy to generate a fast step, very difficult to generate an "infinitely short" pulse (or an approximation of).
• The step contains much more energy and will generate a much larger response. Whereas a pulse would only generate a small blip on the output. Signal-to-noise ratio is much better with a step.
• An impulse would not allow to test for slew rate. It would provide little information.
• Thus the step is easier to use in practice. If you want the impulse response, do a step, then differentiate.

Answer 2

An impulse, i.e. hit it with a hammer, is not very friendly, particularly in systems that have mechanical bits and pieces.

A perfect impulse cannot be generated, so you have to tailor the pulse duration to the system.

A pulse that gives meaningful response data needs to be relatively strong, and that means high amplitude (strength = area = height x duration, and duration=small, therefore height=large)

To get the step response from the impulse response you have to integrate, which means you need to know initial conditions.

An impulse response does not give DC gain information readily; a step response does.

A step isn't as violent as an impulse.

A step is a step regardless of the system dynamics.

You can get the impulse response from the step response by differentiating - and doesn't require initial conditions.

The step response is often the inherent integral of the impulse response (eg motor velocity to motor displacement) and integration has noise-rejection characteristics.

Answer 3

It's possible to describe an "almost perfect" step function using positive parameters δ, ε, and ε', such that:

1. For all values of t<-δ, the output will be between -ε and +ε.
2. For all values of t>+δ, the output will be between 1-ε and 1+ε.
3. For all other values of t, the output will be between -ε' and 1+ε'.

Graphically, such functions may be described by saying that their output is always within an "envelope" that looks like:

 :                █
 :                █▀▀▀▀▀▀▀▀▀▀▀▀▀▀ y=1
 :                █                
 :                █                
 :▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀▀█▔▔▔▔▔▔▔▔ y=0
 :                ▀ 

Any application that would work with all functions that would meet the requirements for some particular values of δ, ε, and ε' would be satisfied by any function that met the requirements for smaller values of those parameters. The exact position of the function within the envelope may be poorly defined, but most applications wouldn't be interested in that level of detail beyond having upper limits for δ, ε, and ε'. This thus makes it easy to describe a set of functions that will be "good enough" for a particular purpose, and ensure that the behavior of a real-world system is a member of that set.

An "almost perfect" impulse function, by contrast, cannot be described in such a fashion. Behavior may be well-defined at the points where nothing is happening, but the part of the domain where behavior is least well-defined is also the part of the domain where everything interesting is happening.