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I understand that I should repreatedly use deMorgan's theorem until I am left only with NAND/NOT gates. This is easy when the starting function is an SOP/POS. However when it isn't, I get confused as to what my steps should be (both agebraically and graphically). Consider the function below:

enter image description here

whose circuit looks like this: enter image description here

I think I can do it algebraically but apparently it is possible to do it graphically (which should be the simpler approach). I can't get my head around doing it graphically, as the process is a little more involved than it is with SOP/POS. Can anyone give me a hand?

StainlessSteelRat
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Swifty
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    Rather than So much problem description, you could share how much you are able to solve. If there is a tweak or hint needed, then definitely people will help. But expecting help without sharing what you have done till now makes many lose interest in the question. – User323693 Feb 12 '17 at 03:08
  • Possible duplicate of http://electronics.stackexchange.com/questions/203605/what-is-the-point-of-converting-everything-to-nand-nor-and-how-do-you-do-it-righ/203612#203612 –  Feb 12 '17 at 12:33
  • Why does the function need to be a sum-of-products or product-of-sums for you to use that method? – user253751 Feb 27 '17 at 23:03

2 Answers2

0

That expression has ANDs, ORs(+), and NOTs('). You already have the NOT. A NAND followed by NOT is AND. A NAND preceeded by NOT for each input is OR.

analogsystemsrf
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0

So graphically, replace each gate with it's NAND equivalent.

For an OR gate:

schematic

simulate this circuit – Schematic created using CircuitLab

Remove double NOT gates (if they occur). NAND2 and NAND3 can be removed in the following schematic.

schematic

simulate this circuit

Edit...

First part of circuit:

schematic

simulate this circuit

In this circuit, NAND3 & NAND4 and NAND7 & NAND8 are redundant and can be removed.

schematic

simulate this circuit

StainlessSteelRat
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