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The company I am working for is developing a patient-connected device intended to deliver Functional Electrical Stimulation to a connected user. We are currently struggling to pass the radiated emissions standard.

We have located the source of our problem to our isolated DC/DC power supply by shutting off the isolated power

enclosure

Enclosure

emissions results DCDC enabled

DCDC enabled

emissions results DCDC disabled

DCDC disabled

We also notice that when we disconnect the external patient leads, our radiated emissions are reduced significantly. The signals that we are sending down the cable are biphasic pulses with the following characteristics

  • Pulse Width = 500us
  • Pulse Amplitude = 150V
  • InterPhase Interval = 100us
  • Frequency = 60hz biphasic pulse We are in the process of designing a new board with the following features

  • Get rid of internal patient lead cable in favor of a right angle connector

  • Y capacitors across the isolation barrier of the DCDC converter
  • Pi filter and Common mode choke on the input of the DCDC converter
  • Pi filter at the output of the DCDC converter
  • LC filters at the patient connector

However I am still concerned that the external patient cables will radiate excess EMI. Since they are patient cables we are limited on the filtering that we can do and we are not able to shield the cables to the enclosure because it is made of plastic. Does anyone have any suggestions for what we can do to make our device more compliant, specifically as it relates to the patient cables?

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    Others better than me can discuss the patient cabling ideas. But I'm wondering if you've considered replacing your isolated DC/DC converter with a spread spectrum version. If you also provide a clock to a micro, and if it has EMI as well, there are also spread spectrum chips for that, too. – jonk Nov 21 '16 at 21:24
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    You might want to trim that photo of the device some more. The name of your company shows in the paperwork underneath it. – JRE Nov 21 '16 at 21:28
  • @jonk I will certainly look into that, however it has been hard to find a variety of DC/DC converters that meet our 4Kv isolation requirements as well as our 5W, 12V power requirements. – John Taylor Nov 21 '16 at 21:32
  • DC/DC: from what are you driving that? (I would've expected a grid->DC, i.e. AC/DC converter) – Marcus Müller Nov 21 '16 at 22:03
  • @MarcusMüller Our power distribution network goes from the grid to a 24V AC/DC converter then to a 24V-12V buck regulator, then to the 12V-12V DCDC isolated power supply. Everything before the DCDC was running when we took the data for the second plot. – John Taylor Nov 21 '16 at 22:17
  • Ah, ok. Hm. My gut feeling is that 12V->12V is actually a relatively hard-to-do-with-low-noise design (probably being SEPIC, anyway. Isolation and stuff); can you try with 24V->12V isolated power supply? The voltage "overhead" would allow for less "aggressive" switching – Marcus Müller Nov 21 '16 at 22:20
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    When you shut off the DC/DC, did you power the patient side with something else like a battery? If not, the source of the noise may not be the DC/DC but the electronics that was not operational? – owg60 Nov 21 '16 at 23:16
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    We did not do that in the actual test chamber, but we were able to confirm with a spectrum analyzer that the processors and other power supplies on the isolated side of the DC/DC didn't contribute to the noise nearly as much as the DC/DC. – John Taylor Nov 22 '16 at 00:40

1 Answers1

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So the rule is: Current will follow the path of lowest Impedance There is a radiating source on your board, you've isolated that section board and you've created a nice antenna by attaching the cable to it. The preferred pathway (and lowest impedance pathway) is out the cable and into the air.

One way to control the current would be to put caps and attenuate the signal where the cable connects to the PCB, this would sink the current out at the cable.

The better (and easier way) would be to increase the impedance of the cable. I can't speak for your signals because you haven't defined what they are, if you have high frequency signals in your cable you will attenuate those too so use caution. A ferrite is a good way to increase the inductive impedance of the cable without interfering with your PCB. You could put it on the inside of the box around the cable that goes to the outside of the box (the internal patient lead, I hope your not putting that into the patient) .

Another way to increase the inductance would be to put filtering on the PCB at the connector to allow your frequency of interest to pass through and to attenuate the RF.

Redesigning the board and getting clocks and converters away from the the cable may also help. If the main source is that DC to DC isolation converter, you may want to put a heavy filter after the converter on the V+ Side and stop the problem before it gets to the rest of the PCB/Design.

Get Electromagnetic Compatibility Engineering by Henry W Ott

schematic

simulate this circuit – Schematic created using CircuitLab

Voltage Spike
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  • Thanks for your input. I have added information on the signals that we expect out of the patient cables. We attempted a fix by adding ferrite beads in series (1.5kohm @ 100Mhz) and a shunting capacitor to each line (10nF) between the internal patient lead cable and the external patient lead cable on the PCB mounted to the enclosure. Unfortunately this did not seem to help at all. In our new design we plan on removing the internal patient cable in favor of a right angle connector and also plan to add filtering to the input and output of the DCDC. – John Taylor Nov 21 '16 at 22:26
  • Did you try a clamp on ferrite? – Voltage Spike Nov 21 '16 at 22:40
  • We did not, unfortunately. – John Taylor Nov 21 '16 at 22:43
  • Actually, looking at your signal that might interfere too much just on the cable itself. Another thing I'd suggest is shielding from end to end on the cable with ferrites on the shield make sure your shielding inductance is low as any parasitic inductance between connectors back to your board will create problems. The idea with shields is you need a conductor around your cable 'antenna' to capacitively shunt the currents back to your board. – Voltage Spike Nov 21 '16 at 22:44
  • Do you have any suggestions on how to ground the shield since we don't have a grounded enclosure? – John Taylor Nov 22 '16 at 00:41
  • Yep, I would have a solid ground connection right to the PCB. Shielding will probably change your cabling, you can get connectors with a shield, you can buy (it can be hard to find) multi conductor cables with a shield on them. For experiments sakes, If you have some wide copper tape you could try putting two strips of tape on the outside of the cable (careful its sharp, also if your going around the connector make sure you insulate it). – Voltage Spike Nov 22 '16 at 00:51
  • Then ground the end of the shield to the PCB by scraping a section of the ground plane if its accessible or you might have to solder it to a ground pin on the connector. The lower impedance/inductance you can maintain with the shield the better. – Voltage Spike Nov 22 '16 at 00:51
  • It really depends on if its the DC to DC converter that's causing the issue or your signal. Try testing the instrument with just the DC\DC on and see if you get the same RF pattern. – Voltage Spike Nov 22 '16 at 00:53
  • The test that we ran was with just the DC/DC on. No signals going down the external cable. – John Taylor Nov 22 '16 at 14:43
  • Forget the shielding idea then. I'd try filtering the output of the DC/DC then, with an RC or LC circuit on the output. Put the power filter caps closer to the DC/DC converter. One thing you might try is putting a few caps in parallel (0.1uf, 1uf and 10uf) between the positive and negative terminals of the DC/DC. Right now it looks like your filter caps are located a few inches from the DC/DC and there would be too much series inductance for the caps to be effective at higher frequencies. At lower frequencies the RF currents need to be shunted back to the source (the DC/DC converter) – Voltage Spike Nov 22 '16 at 18:21
  • By the way, current explores *all* possible paths, proportional to conductivity. All. Not just the path with highest conductivity. – analogsystemsrf Feb 16 '17 at 08:30
  • Usually there is one path with low impedance and that is the path you need to worry about, either for shunting the current or blocking it. – Voltage Spike Feb 16 '17 at 16:51