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I am planning to use a RC circuit to satisfy power up ramp rate requirements. Does the R value depends on system current?

Null
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engineer
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1 Answers1

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Yes, basically it is always a tradeoff:

If the RC filter drives some high-impedance device (Opamp, ADC, NE555, ...)

  • If you set R too low, the circuit will consume more power, and the capacitor will need to be bigger, which can become physically impractical / too expensive.
  • If you set R too high, the flowing current will be too small and the small current flowing to the device "reading" the capacitor voltage (Opamp, ADC, NE555, whatever, ...) will become significant. Then your time constant will not be accurate anymore.

So choose the R value so it sets a current through the capacitor that largely (10x, 100x depending on the accuracy) dominates the input leakage of the "reading" device.

If the RC filter directly drives the whole load (your case, it seems)

  • If you set R too high, there will be a high voltage drop between the supply and the circuit, so the circuit won't work.
  • If you set R too low, the capacitor will need to be bigger, which can become physically impractical / too expensive.

So compute the higher R limit, which is (Vsupply - Vload) / Iloadmax, with

  • Vsupply: your supply voltage
  • Vload: the voltage required by the circuit behind the RC filter
  • Iloadmax: the maximum current that the circuit can draw

and the lower R limit will depend on your time constant and the maximum capacitor value you can afford to use.

However, you must then account for the load current itself when calculating the required capacitor value. Because the time to reach the target voltage will be highly dependant on the load current, not just the RC time constant. But honestly, I am unable to give quickly an equation for this. I would suggest making a quick simulation with LTspice, here. Or try the real circuit with several capacitor values, once you choose your R to some value just below the higer limit calculated with the above equation.

Now, what is a better idea

The problem is that, if your load have big current requirements, the computed max R value will probably not lead to a realistic C value. So, what people usually do is to use a soft-start circuit using a MOSFET. This way, at steady state, the resistance between the supply and your load becomes negligible (so there is no voltage drop).

Here is an excellent suggestion for this: How to limit inrush current?

dim
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  • I understand that R should be chosen such a way that it is capable of allowing current flow of system Is that correct? – engineer Apr 25 '16 at 15:43
  • Ooook, now I understand. There is no high-impedance (opamp, whatever, ...) device behind the RC filter, right ? You want to put the load **directly** behind the RC filter ? I will edit the answer then. – dim Apr 25 '16 at 18:29
  • yes, need to add RC time constant for device VDD to meet the power ramp requirement of device. – engineer Apr 25 '16 at 19:58