Here is my circuit. It works well, as described in a book, but I want to understand it better, so I want to check voltage on capacitor. But when I do it, LED doesn't blink and voltage goes up to 4V. When I turn off multimeter - it works again. Мultimeter is connected to capacitor directly. What did I do wrong?
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Is this an analog multimeter or a digital one? – Nov 29 '14 at 21:03
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If it goes up to 4V, input impedance of the multimeter is 1 MOhm, it is a digital one. You should try with another multimeter, a better one. – Roger C. Nov 29 '14 at 21:10
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1Mohm is a bit low for a DMM. – Ignacio Vazquez-Abrams Nov 29 '14 at 21:11
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Try using a scope. – Leon Heller Nov 29 '14 at 21:13
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To understand simple circuits I always recommend using a simulator; it rarely suffers from similar issues. – PlasmaHH Nov 29 '14 at 21:25
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related: [Why can a voltmeter still measure potential difference if it has a (theoretically) infinite resistance?](http://electronics.stackexchange.com/q/140554/17608) – Phil Frost Nov 30 '14 at 02:15
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@PlasmaHH which one do you use? – Ishayahu Dec 06 '14 at 20:10
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@RogerC. which one? How can I know input impedance before buying? – Ishayahu Dec 06 '14 at 20:38
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@Ishayahu, you can look its datasheet in internet before buying. For example UT61 is a rather low cost DMM, you can read its datasheet in http://uni-trend.com/manual2/UT61English.pdf . Its input impedance is 10 M\$\Omega \$ (page 17). – Roger C. Dec 06 '14 at 21:02
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@Ishayahu: ltspice; search on this site, there is a question with lists of possible simulators to try as answers. – PlasmaHH Dec 07 '14 at 21:00
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Obviously your multimeter influences your circuit. To measure the voltage across the capacitor some current must flow through the multimeter. The amount of current through the multimeter is defined by the measured voltage and the internal resistance of the multimeter.
With the high resistor value of \$470 K\Omega\$ even an internal resistance as high as \$1 M\Omega\$ has a remarkable impact on your circuit.
When you have the parts at hand, you could change your circuit to use \$47 K\Omega\$ and \$22 \mu F\$. The time from flash to flash shouldn't change. However the flash duration would be 10 times longer.

Kitana
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Another quick solution could be to swap 15k and 27k resistors, maybe voltage is not enough to light the LED though – Roger C. Nov 29 '14 at 21:40
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It doesn't work for me, because of transistor. The LED lights without blink( If I understand right, the voltage on capacitor in my case is only 2V? – Ishayahu Dec 06 '14 at 20:08
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@Ishayahu - Transistor??? We are talking about a thyristor. Where do you have the 2V from??? What have you exactly done that doesn't work for you? – Kitana Dec 06 '14 at 20:51
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@Kitana sotty, thyristor) I use multimeter to measure voltage on capacitor. In that case LED doesn't blink and I don't understand why – Ishayahu Dec 07 '14 at 09:32