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It is my understanding that a highly doped, thin depletion region, reverse-biased P-N junction at low voltage can cause quantum mechanical tunneling. This (or sometimes avalanche breakdown) is used in some hardware random number generators. However, is the noise created in the junction truly quantum mechanically random, or is it chaotic but deterministic?

bsamek
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    The only real difference between "random" and "deterministic" is the amount of knowledge of the observer. – Ignacio Vazquez-Abrams Apr 03 '14 at 17:50
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    Are you sure? [This white paper](http://www.idquantique.com/images/stories/PDF/quantis-random-generator/quantis-whitepaper.pdf) claims that their RNG products are superior because they use a truly random process, whether a photon is reflected by a semi-transparent mirror. They contrast this with chaotic but deterministic processes like the Zenner diode. I'm curious if it's true that the Zenner diode isn't truly random. In cryptography, you have to be concerned that your attacker will be able to predict a deterministic process even if you can't. Quantum processes are in theory unpredictable. – bsamek Apr 03 '14 at 18:13
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    I can't be absolutely certain, but only because we haven't yet reached a point where we can call quantum processes "deterministic". But absence of evidence is not the same as evidence of absence. – Ignacio Vazquez-Abrams Apr 03 '14 at 18:16
  • @IgnacioVazquez-Abrams Interesting statement- what school of thought is that? – Spehro Pefhany Apr 03 '14 at 21:17
  • @SpehroPefhany: I don't know that it has a specific name, but it's based on the belief that no matter how much we know, no matter how far we've come, we're basically still at the starting line knowing nothing at all. – Ignacio Vazquez-Abrams Apr 03 '14 at 21:27
  • @IgnacioVazquez-Abrams Okay... I started looking at the Wiki page on Interpretations_of_quantum_mechanics and got lost. – Spehro Pefhany Apr 03 '14 at 21:40
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    @Spehro: I think Ignacio is coming out of older discussions about "hidden variables." A position taken by Einstein was that there may be hidden variables that govern quantum statistics and that if that underlying theory could be worked out, then determinism could be restored and what used to be "random" wouldn't be anymore. But Bell's inequality provides a very sensitive test which now experimentally appears to exclude all "local hidden variable" theories. – jonk Apr 04 '14 at 00:18
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    @jonk Exactly. And this means that there is a distinction between random processes with hidden variables and true quantum processes. In the former it might be a practical impossibility to determine the system's future states based on prior knowledge. In the latter case it is a theoretical impossibility. Hence my question. – bsamek Apr 04 '14 at 04:04
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    @IgnacioVazquez-Abrams *"The only real difference between "random" and "deterministic" is the amount of knowledge of the observer"* That ceases to be true in quantum mechanics, and it's not just theoretical. Look up experiments demonstrating violations of the so-called "Bell Inequality" which prove that *either* 1) The randomness in quantum mechanics is not due to lack of information of the observer, or 2) The laws that govern the universe are not local, i.e. distant parts of the universe affect each other faster than the speed of light. – DanielSank Dec 30 '16 at 04:18

1 Answers1

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The noise that is created is truly random as it is generated by recombination of electrons with the atoms on the other side of the junction. The mean power density (RMS) can be calculated using the following formula:

$$i_n = \sqrt{2 I q \Delta B}$$

where \$q\$ is the electron charge, \$I\$ is the current that runs through the diode and \$\Delta B\$ is the bandwidth of the detector that measures the noise.

Apart from that, it is a stochastic process and therefore random. Read more about it here:

http://en.wikipedia.org/wiki/Noise_(electronic)#Shot_noise

DanielSank
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einball
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  • Does this apply to both avalanche and Zenner noise? – bsamek Apr 03 '14 at 18:14
  • Zener breakdown noise is shot noise if I remember that correctly. The diode type does not matter. A Zener diode will have an electron avalanche when it reaches its breakdown voltage (reverse biased). – einball Apr 03 '14 at 18:41
  • @einball: The [noise generator](http://en.wikipedia.org/wiki/noise_generator) and [Zener diode](http://en.wikipedia.org/wiki/Zener_diode) articles seem to say that Zener diodes rated below 7 V produce mostly shot noise, Zener diodes rated above 7 V produce mostly avalanche noise, and Zener diodes near 7 V have a mixture of both. – davidcary Aug 22 '14 at 03:18
  • This answer seems to say that the shot noise is spectrally white, which is incorrect. – DanielSank Dec 30 '16 at 14:39
  • @davidcary Is there any correlation in that dividing line and the one about the direction of the thermal coefficient in relation to the reverse knee voltage (predominantly _zener_ {quantum tunnelling} _effect_ below 5V and _avalanche breakdown_ above 7V)? Oh, hang on it is the same thing if the shot-noise IS from the zener effect. – SlySven Jan 11 '17 at 19:49
  • @DanielSank I just saw this. Please fill in the blanks on the PSD of shot noise for me. I ẃill update my answer. – einball Jan 23 '21 at 15:01
  • @einball I would rather just write a full answer myself than to try to explain how to compute the spectral density of shot noise in a comment :-) I'm sure you can find details online or in a book though. – DanielSank Jan 23 '21 at 23:25
  • @DanielSank Alright :) – einball Jan 24 '21 at 07:48